[" 10. langleas ulich is onore acide "c,pH=02" ."1+02+02=05" mash "],[" or "pH=6" ? "]

1.02 + 6 = ?

When 0.02 mole of an alkali is added to an acid buffer , the pH changes from 4.75 to 4.8 the buffer capacity is

The Ph of basic buffer mixtures is given by : Ph=Pk_(a)+ log (["Base"])/(["Salt"]) whereas Ph of acidic buffer mixtures is given by : Ph = pK_(a)+"log"(["Salt"])/(["Acid"]) . Addition of little acid or base although shows no appreciable change in Ph for all practical purposes, but sicne the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. The volume of 0.2 m NaOH needed to prepare a buffer of pH 4.74 with 50 mL of 0.2 m acetic acid pH_(b) of CH_(3)COO^(-)=9.26 is :

Calculate the pH of the following solutions obtained by mixing : (a)equal volumes of two solutions with pH=4 and pH=10 (b)400 mL of solution with pH=3 and 100 mL of solution with pH=4 (c )200 mL of 0.1 M NaOH and 300 mL of 0.2 KOH

Calculate the pH of 0.2 M H_2SO_4 .

In 0.02 M solution of perchlorid acid (HClO_(4)) at 298 K the sum of pH and pOH is equal to