For the curve `x y=c ,` prove that the portion of the tangent intercepted between the coordinate axes is bisected at the point of contact.

In the curve x^(a)y^(b)=K^(a+b), prove that the potion of the tangent intercepted between the coordinate axes is divided at its points of contact into segments which are in a constant ratio.(All the constants being positive).

The equation of the curve in which the portion of the tangent included between the coordinate axes is bisected at the point of contact, is

The equation of the curve not passing through origin and having portion of the tangent included between the coordinate axes is bisected the point of contact is

Prove that the segment of tangent to xy=c^(2) intercepted between the axes is bisected at the point at contact .

The equation straight line such that the portion of it intercepted between the coordinate axes is bisected at the point (h,k) is :

Find the equation of the line whose portion intercepted between the axes is bisected at the point (3,-2)

A line passes through (-3,4) and the portion of the line intercepted between the coordinate axes is bisected at the point then equation of line is (A)4x-3y+24=0(B)x-y-7=0(C)3x-4y+25=0 (D) 3x-4y+24=0

The curve that passes through the point (2,3) and has the property that the segment of any tangent to it lying between the coordinate axes is bisected by the point of contact,is given by

The equation of the line which is such that the portion of line segment intercepted between the coordinate axes is bisected at (4,-3) is (a) 3x+4y=24(c)3x-4y=24 (b) 3x-4y=12 (d) 4x-3y=24..