If x is real, the expression ` (x+2)/(2x^2 + 3x+6)` takes all value in the interval

If x is real and the expression (x^(2) + 2x - 11)/( x - 3) takes all values which do not lie between a and b, then find a and b

If the expressions (x-p)/(x^(2)-3x+2) takes all real value for x in R , then find the bounts for p.

If x is real then (x^(2)-x+c)/(x^(2)+x+2c) can take all real values if

IF x is real then the value of ( x ^2 - 3x +4)/( x^2 +3x +4) lies in the interval

For x in R, the expression (x^(2)+2x+c)/(x^(2)+4x+3c) can take all real values if c in

Find the interval in which 'm' lies so that the expression (mx^(2)+3x-4)/(-4x^(2)+3x+m) can take all real values,x in R.