In the reaction,
`3BrO^(-)rarrBrO_(3)^(-)+2Br^(-)` (aqueous alkaline medium at `80^(@)C`) the vlaue of the rate constant in the rate law in terms of `--(d)/(dt)[BrO^(-)]` is `0.056 L "mol"^(-1)s^(-1)`. What will be the rate constant when the law is stated in terms of `(d)/(dt)[BrO^(-)]`?

For the reaction: aA + bB rarr cC+dD Rate = (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt) For reaction 3BrO^(ɵ) rarr BrO_(3)^(ɵ) + 2Br^(ɵ) , the value of rate constant at 80^(@)C in the rate law for -(d[BrO^(ɵ)])/(dt) was found to be 0.054 L mol^(-1)s^(-1) . The rate constant (k) for the reaction in terms of (d[BrO_(3)^(ɵ)])/(dt) is

For the reaction: aA + bB rarr cC+dD Rate = (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt) For reaction 3BrO^(ɵ) rarr BrO_(3)^(ɵ) + 2Br^(ɵ) , the value of rate constant at 80^(@)C in the rate law for -(d[BrO^(ɵ)])/(dt) was found to be 0.054 L mol^(-1)s^(-1) . The rate constant (k) for the reaction in terms of (d[BrO_(3)^(ɵ)])/(dt) is

The rate law for the reaction 2A to products is given by : rate =9.0 xx10^(-5) A mol L^(-1) S^(-1) . What is the decompostion rate when A=0.250 mol / litre ?

In the reaction BrO^(-) (aq) + 5Br^(-) (aq) + 6H^+ rarr 3Br_2(l) + 3H_2O the rate of apperance of (Br_2) is related to the rate of disapperance of Br^(-) as follows

The rate of formation of ammonia by the reaction: N_2+3H_2rarr2NH_3 expressed as (d[NH_3]/(dt))=2.5xx10^(-4)mol L^(-1) s^(-1) The rate of consumption expressed in terms of H_ 2 as (-d[H_2]/(dt)) will be

In the reaction BrO_3^(-)(aq) + 5Br^(-) + 6H^(+) rarr 3Br_2 + 3H_2O the rate of appearance of bromine is relate to the rate of disappearance of bromide ions as

In the reaction BrO_(3)^(-)(aq)+ 5Br^(-)+6H^(+) rarr 3Br_(2)+3H_(2)O the rate of appearance of bromine is related to the rate of disappearance of bromide ions as :