The mass of Earth is `6xx10^(24)` kg and that of moon is `7.4xx10^(22)` kg. if the distance between the earth and the moon is `3.84xx10^(5)` km, calculate the force exerted by earth on the moon. Given `G=6.7xx10^(11) Nm^(2)//kg^(2)`.

Answer

`F=2.01xx10^(20)`newtons

Explanation

The force exerted by one body is given by the Newton's formula
`F=Gxx(m_(1)xxm_(2))/r^(2)`
Here Gravitational ,`G=6.7xx10^(-11)Nm^(2)kg^(-2)`
mass of the earth ,`m_(1)=6xx10^(24)kg`
Mass of the moon `m_(2)=7.4 xx 10^(22)kg `
And Distance between the `r=3.84xx10^(5) `km
earth and moon
`=3.84xx10^(5)xx1000m`
`=3.84 xx 10^(8)`
Putting these values in the above formula we get
`F=(6.7xx10^(-11)xx6xx10^(24)xx7.4xx10^(22))/(3.84xx10^8)^(2)`
`F=2.01xx10^(20)`newtons
Thus the graviational froce exterted by the earth on the moon is `2.01xx10^(20)` newtons .And this is an extermely large force .It is the extremely large gravitaional force exerted by the earth on the moon which makes the moon revolve around the earth .