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The mass of 2 m^(3) of steel is 15600 kg...

The mass of `2 m^(3)` of steel is 15600 kg. Calculate the density of steel in SI units .

A

`31200 Kg//m^3`

B

`780 Kg//m^3`

C

`7800 Kg//m^3`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
C
We know that: Destiy `=("Mass")/("Volume")`
`=(15600 kg) /(2 m^(3))`
`7800 kg//m^(3)`
Thus the density of steel in SI units is = `7800kg/ /m^(3)`
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Knowledge Check

  • The greatest length of a steel wire that can hang without breaking is 10 km. I the breaking stress for steel is 8.25xx10^(8)N//m^(2) . Then the density of the steel is (g=10m//s^(2))

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