The relative density of silver is 10.8 If the density of water be `1.0xx10^(3) kg m^(-3)` calculate the density of silver is SI units.

Explanation

We know that :
`"Relative Density of a substance"=("Density of the substance ")/("Density of water " )`
Density of sliver =? (To be calculated )
Density of water `=1.0 xx 10^(3) kg m^(-3)`
Now putting these values of realtive density of silver and density of water in the above formula ,we get :
`10.8=("Density of silver" )/(1.0xx10^(3)`
So Density of silver `=10.8xx1.0xx10^(3) kg m^(-3)`
Thus the density of silver in SI units is `10.8xx10^(3) kg m^-(3)`.This can also be written as `10800 kg m^(-3)`