What is the force of gravity on a body of mass 150 kg lying on earth (Mass of earth` =6 xx 10^(24) kg ` Radius of earth `= 6 .4 xx 10^(6) m G= 6 .7 xx 10-11 Nm^2//kg^2)`

Answer

To find the force of gravity on a body of mass 150 kg lying on Earth, we can use Newton's universal law of gravitation, which states:

\[ F = \frac{G \cdot M \cdot m}{r^2} \]

Where:
- \( F \) is the gravitational force,
- \( G \) is the universal gravitational constant (\( 6.7 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \)),
- \( M \) is the mass of the Earth (\( 6 \times 10^{24} \, \text{kg} \)),
- \( m \) is the mass of the body (\( 150 \, \text{kg} \)),
- \( r \) is the radius of the Earth (\( 6.4 \times 10^{6} \, \text{m} \)).

### Step-by-Step Solution:

1. **Identify the values**:
- Mass of the body, \( m = 150 \, \text{kg} \)
- Mass of the Earth, \( M = 6 \times 10^{24} \, \text{kg} \)
- Radius of the Earth, \( r = 6.4 \times 10^{6} \, \text{m} \)
- Gravitational constant, \( G = 6.7 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \)

2. **Substitute the values into the formula**:
\[ F = \frac{(6.7 \times 10^{-11}) \cdot (6 \times 10^{24}) \cdot (150)}{(6.4 \times 10^{6})^2} \]

3. **Calculate the denominator**:
\[ (6.4 \times 10^{6})^2 = 40.96 \times 10^{12} = 4.096 \times 10^{13} \]

4. **Calculate the numerator**:
\[ 6.7 \times 10^{-11} \cdot 6 \times 10^{24} \cdot 150 = 6.7 \cdot 6 \cdot 150 \times 10^{-11 + 24} = 6.7 \cdot 6 \cdot 150 \times 10^{13} \]
- Calculate \( 6.7 \cdot 6 = 40.2 \)
- Then \( 40.2 \cdot 150 = 6030 \)
- So, the numerator becomes \( 6030 \times 10^{13} \)

5. **Combine the results**:
\[ F = \frac{6030 \times 10^{13}}{4.096 \times 10^{13}} = \frac{6030}{4.096} \approx 1472.16 \, \text{N} \]

### Final Answer:
The force of gravity on a body of mass 150 kg lying on Earth is approximately **1472.16 N**.