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The mass of a planet is 6xx10^(24) kg an...

The mass of a planet is `6xx10^(24)` kg and its diameters is `12.8 xx 10^(3)` km. If the value of gravitational constant be `6.7xx10^(-11) NM^(2)//Kg^(2)` ,Calculate the value of acceleration due to gravity on the surface of the planet.What planet could this be ?

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The correct Answer is:
`9.8 m//s^(2);Earth`
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LAKHMIR SINGH & MANJIT KAUR-GRAVITATION-Exercise
  1. What do you undersatand by the term accelation due to gravity of earth...

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  2. State and explain briefly Keplars laws of planetary motion.

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  3. The mass of a planet is 6xx10^(24) kg and its diameters is 12.8 xx 10^...

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  4. A body is thrown vertically upward with velocity u, the greatest heigh...

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  5. The mass of moon is about 0.012 times that of earth and its diameter i...

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  6. The value of g on the surface of the moon

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  7. The atmosphere is held to the earth by

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  8. The force of attraction between two unit point masses separated by a u...

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  9. The weight of an object at the center of the earth of radius R is

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  10. Two object of different masses falling freely near the surface of moon...

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  11. Law of gravitation gives the gravitational force between

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  12. Two particles are placed at some distance. If the mass of each of the ...

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  13. In the relation F=G M m//d^(2), the quantity G

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  14. The gravitational force of attraction between two objects is x. Keepin...

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  15. According to one of the Kepler's laws of planetary motion:

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  16. If the distance between two masses is increased by a factor of 5, by w...

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  17. Universal law of gravitation states that every object exerts a gravita...

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  18. Suppose a planet exists whose mass and radius both, are half those of ...

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  19. Name the quantity whose one of the units is pascal (Pa)

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  20. State whether the following statements are true or false: (a) The b...

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