How much work is done in moving a charge of 2 coulombs from a point at 118 volts to a point at 128 volts?

Options

A. 10 J
B. 15 J
C. 20 J
D. 25 J

Answer

C

Explanation

We know that:
Potential difference `= ("Work done")/("Charge moved")`
or `V = (W)/(Q)`
Here, Potential difference, `V = 128 - 118`
= 10 volts
Work done, `W = ?` (To be calculated)
And, Charge moved, `Q = 2` coulombs
Putting these values in the above formula, we get:
`10 = (W)/(2)`
or `W = 10 xx 2`
Thus, Work done, `W = 20` joules