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A copper wire of length 2m and area of c...

A copper wire of length 2m and area of cross-section `1.7 xx 10^(-6)m^(2)` has a resistance of `2 xx 10^(-2)`ohms. Calculate the resistivity of copper.

A

`1.7 xx 10^(-8)`

B

`1.7 xx 10^(-9)`

C

`1.7 xx 10^(-10)`

D

`1.7 xx 10^(-11)`

Text Solution

Verified by Experts

The correct Answer is:
A
The formula for resistivity is:
Resistivity, `rho = (R xx A)/(l)`
Here, Resistance, `R = 2 xx 10^(-2)Omega`
Area of cross-section, `A = 1.7 xx 10^(-6)m^(2)`
And, Length, `l = 2m`
So, putting these values in the above formula, we get:
`rho = (2 xx 10^(-2) xx 1.7 xx 10^(-6))/(2)`
`=1.7 xx 10^(-8) Omegam`
Thus, the resistivity of copper is `1.7 xx 10^(-8)` ohm-metre.
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Knowledge Check

  • A nichrome wire of length 100 cm and area of cross-section 0.5 m m^(2) has a resistance of 2.2 Omega . The resistivity of nichrome is

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