A current of 4A flows through a 12V car headlight bulb for 10 minutes. How much energy transfer occurs during this time?

Explanation

Energy = Power `xx` Time
or `E = P xx t` .......(1)
First of all we should calculate power P by using the current of 4A and voltage of 12 V.
Now, `P = V xx I`
So, `P = 12 xx 4`
or, Power, `P = 48` watts
`= (48)/(1000)` kilowatts
Thus, Power, `P = 0.048 kW`
And, Time, `t = 10` minutes
`= (10)/(60)` hours
`= (1)/(6)` hours
Now, putting `P = 0.048 kW` and, `t = (1)/(6)` hours in equation (1), we get:
`E = 0.048 xx (1)/(6)`
`= 0.008 kWh`
Thus, the energy transferred is 0.008 kilowatt-hour.