A resistance of `25 Omega` is connected to a 12V battery. Calculate the heat energy in joules generated per minute.

Answer

To solve the problem of calculating the heat energy generated per minute by a resistance of 25 ohms connected to a 12V battery, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- Resistance (R) = 25 Ω
- Voltage (V) = 12 V

2. **Use Ohm's Law to find the current (I)**:
- Ohm’s Law states that \( I = \frac{V}{R} \).
- Substitute the values:
\[ I = \frac{12 \text{ V}}{25 \text{ Ω}} = 0.48 \text{ A} \]

3. **Calculate the heat energy (H) generated using the formula**:
- The formula for heat energy generated due to resistance is given by Joule's law:
\[ H = I^2 R \]
- Substitute the current value into the formula:
\[ H = (0.48 \text{ A})^2 \times 25 \text{ Ω} \]
- Calculate \( I^2 \):
\[ (0.48)^2 = 0.2304 \]
- Now calculate \( H \):
\[ H = 0.2304 \times 25 = 5.76 \text{ J/s} \]
- This value (5.76 J/s) represents the heat energy generated per second.

4. **Convert the heat energy to per minute**:
- Since we need the heat energy generated per minute, multiply the value by 60 (the number of seconds in a minute):
\[ H_{\text{per minute}} = 5.76 \text{ J/s} \times 60 \text{ s} = 345.6 \text{ J} \]

5. **Final Result**:
- The heat energy generated per minute is **345.6 joules**.