Compute the heat generated while transferring `96000` coulombs of charge in one hour through a potential difference of `50 V`.

Explanation

First of all we will calculate the current (I) by using the given values of charge (Q) and time (t). We know that:
Current, `I = (Q)/(T) = (96000C)/(1h) = (96000C)/(60 xx 60 s)`
or `I = 26.67 A`....(1)
We will now calculate the resistance by using Ohm's law:
Resistance, `R = (V)/(I) = (50V)/(26.67 A)`
or `R = 1.87 Omega` ......(2)
And, Time, `t = 1h = 60 xx 60s`
`= 3600 s` ..(3)
Heat generated, `H = I^(2) xx R xx t`
`=(26.67)^(2) xx 1.87 xx 3600 J`
`= 4788397J`
`= 4.97 xx 10^(6)J` or `4.8 xx 10^(6)J`
Thus, the heat generated is `4.8 xx 10^(6)` joules.