An electric kettle rated as 1200 W at 220 V and a toaster rated at 1000 W at 220 V are both connected in parallel to a source of 220 V. If the fuse connected to the source blows when the current exceeds. 9.0 A, can both appliances be used at the same time ? Illustrate your answer with calculations.

Explanation

To determine whether both the electric kettle and the toaster can be used at the same time without blowing the fuse, we will perform the following calculations step by step.

### Step 1: Calculate the total power of the appliances
The electric kettle has a power rating of 1200 W and the toaster has a power rating of 1000 W. Since they are connected in parallel, the total power (P_total) can be calculated as:

\[ P_{\text{total}} = P_{\text{kettle}} + P_{\text{toaster}} = 1200 \, \text{W} + 1000 \, \text{W} = 2200 \, \text{W} \]

### Step 2: Calculate the total current drawn by the appliances
Using the formula for power, we can find the total current (I_total) drawn by the appliances when connected to a voltage of 220 V. The formula relating power (P), voltage (V), and current (I) is:

\[ P = V \times I \]

Rearranging this gives:

\[ I = \frac{P}{V} \]

Substituting the values we have:

\[ I_{\text{total}} = \frac{P_{\text{total}}}{V} = \frac{2200 \, \text{W}}{220 \, \text{V}} = 10 \, \text{A} \]

### Step 3: Compare the total current with the fuse rating
The fuse connected to the source blows when the current exceeds 9.0 A. From our calculation, the total current drawn by both appliances is 10 A.

Since 10 A exceeds the fuse rating of 9 A, the fuse will blow if both appliances are used at the same time.

### Conclusion
Both the electric kettle and the toaster cannot be used at the same time without blowing the fuse.

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