Rahul went to an electronics shop to get his father's old radio set repaired. The radio mechanic required resistances of `1.5 Omega` and `10 Omega` to repair the radio set properly but he had only a large number of `3 Omega` resistors. The radio mechanic made many attempts but could not get the right combinations of `3 Omega` resistors to obtain `1.5 Omega` and `10 Omega` resistances. Rahul had studied combination of resistors in class X. Rahul thought for a while and then joined some `3 Omega` resistors in two different ways to obtain the required resistances.
(a) How did Rahul obtain `1.5 Omega` resistance by joining a number of `3 Omega` resistors ?
(b) How many `3 Omega` resistors were combined together to obtain `1.5 Omega` resistance ?
(c) How did Rahul obtain `10 Omega` resistance by joining a number of `3 Omega` resistors ?
(d) How many `3 Omega` resistors were combined together by Rahul to obtain `10 Omega` resistance ?
(e) What values are shown by Rahul in this apisode ?

Explanation

(a) In order to obtain `1.5 Omega` resistance, Rahul first combined three `3 Omega` resistors in parallel to obtain a resistance of `1 Omega`. He then connected six `3 Omega` resistors in parallel to obtain a resistance of `0.5 Omega`. These two parallel combinations were then connected in series to obtain a resistance of `1 + 0.5 = 1.5 Omega` (see Figure 1)
(b) Nine `3 Omega` resistors.

(c) In order to obtain `10 Omega` resistance, Rahul first connected three `3 Omega` resistors in parallel to obtain a resistance of `1 Omega`. He then connected three `3 Omega` resistors in series to get a resultant resistance of `9 Omega`. The parallel combination and series combination were then connected in series to obtain a final resistance of `1 + 9 = 10 Omega` (see Figure 2).
(d) Six `3 Omega` resistors.
(e) Rahul showed the values of (i) Knowledge of combination of resistors (ii) Application of knowledge, and (iii) Desire ot help others.