Given the two concentration of HCN `(K_(a)=10^(-9))` are `0.1` M and `0.001` M respectively. What will be the ratio of degree of dissociation?

The ratio of degree of dissociation of HCN when concentrations are 0.1 M and 0.001 M respectively will be

If the dissociation constants of two substances are K_(1) " and " K_(2) respectively , then the ratio of degree of dissociation for a given concentration , is given by

The concentration of HCN and NaCN in a solution is 0.01 M each. Calculate the concentration of hydrogen and hydroxyl ions if dissociation constant of HCN is 7.2 xx 10^(-10)

The ionization constant of phenol is 1.0xx10^(-10) . What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01 M in sodium phenolate?

The ionization constant of phenol is 1.0xx10^(-10) . What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01 M in sodium phenolate?

The ionisation constant of phenol is 1.0xx10^(-10) . What is the concentration of phenolate ion in 0.05(M) phenol solution ? What will be its degree of ionisation if the solution is also 0.01(M) in sodium phenolate?