Calculate de Broglie wavelength associated with an electron moving with a speed of `2 xx 10^(5) ms^(-1)`. Given `h = 6.625 xx 10^(-34)JS, m_(e) = 9.11 xx 10^(-31)kg`.

Explanation

Given `v= 2xx 10^5 ms^(-1)` , `h =6.625 xx 10^(-34)` Js,
`m_c=9.11 xx 10^(-31)` kg
w.k.t.
`lambda=h/(mv) =(6.625xx10^(-34))/(9.11xx10^(-31)xx2xx10^5)` i.e.,
`lambda=3.636xx10^(-9) m =3.636` nm