The plates of a parallel plate capacitor have an area of ` 100 cm^(2)` each and are separated by 3 mm . The capacitor is charged by connecting it to a 400 V supply .
Calculate the electrostatic energy stored in the capacitor .

Explanation

Given `A=100 cm^2 =10^2 xx10^(-4)=10^(-2) m^2` ,
d=3 mm = `3xx10^(-3) ` m ,
V=400 V
Electrical energy
`.E.=1/2CV^2=(epsilon_0AV^2)/(2d)`
i.e., `E=(8.854xx10^(-12)xx10^(-2)xx(400)^2)/(3xx10^(-3))`
i.e., `E=2.361xx10^(-6)` J