" 15."int sec^(2)theta(sec theta+tan theta)^(2)d theta

int sec ^ (2) theta (sec theta + tan theta) ^ (2) dth eta

int sec^(2)theta(sec theta+tan theta)^(2)backslash d theta

int(sec theta)/(sec theta-tan theta)d theta

Evaluate the following w.r.t theta : int frac{sec theta }{sec theta + tan theta} d theta

(1+2sin theta+sin^(2)theta)/(cos^(2)theta)=(sec theta+tan theta)/(sec theta-tan theta)

int(sec theta)/(tan^(2)theta)d theta is.

int(sec^(2)theta d theta)/(tan^(3)theta+4tan theta)

int_(0)^((pi)/(2))(sec theta-tan theta)d theta

If : sec theta * tan theta (sectheta + tan theta) + (sec theta - tan theta) = sec^(n) theta + tan^(n) theta, "then" : n = A)1 B)2 C)3 D)4