" (iv) "x=sin sqrt(t),quad y=e^(sqrt(t))

x=sinsqrt(t),y=e^(sqrt(t)) find dy/dx

The slopee of normal to the curve x=sqrt(t) and y=t-(1)/(sqrt(t)) at t=4 is . . .

x=sqrt(sin 2t),y=sqrt(cos 2 t)

If x= sin sqrtt,y =e^(sqrt( t) ),then (d^(2)y)/(dx^(2))=

If x=sin t sqrt(cos2t) and y=cos tsqrt(sin2t) , find (dy)/(dx) at t=(pi)/(4) .

Find (dy)/(dx) if: x=a(cos t+(1)/(2)ln tan^(2)(t)/(2)) and y=a sin t.x=sin t sqrt(cos2t) and y=cost sqrt(cos2t)

Find ( d^2 y)/(d x^2 ) of the following: x= sin sqrt t , y= sin sqrt t