int((sin theta+cos theta))/(sqrt(sin2 theta))d theta=

int((sin theta+cos theta))/(sqrt(sin 2theta))d theta is equal to

int(sin theta+cos theta)/(sqrt(1+sin2 theta))d theta

int ((sin theta +cos theta ))/(sqrt(sin 2 theta)) d theta is equal to :

int_(0)^( pi)(sin theta+cos theta)/(sqrt(1+sin2 theta))d theta

int (sin theta + cos theta)/(sqrt(sin 2 theta) ) d theta =

Evaluate the following integrals : int ( sin theta + cos theta )/(sqrt(1+sin 2 theta )) d theta

int (cos theta - sin theta)/(sqrt(sin 2 theta) ) d theta=

int(sqrt(cos2 theta))/(sin theta)d theta=

int((sin theta-cos theta)d theta)/((sin theta+cos theta)sqrt(sin^(2) theta cos^(2)theta+sin theta cos theta))