Find the equation of normal to the curve `x=cos theta, y = sin theta" at point "theta = pi/4*`

Find the equation of the normal to the curve x=a cos theta and y=b sin theta at theta

Find the equation of normal to the curve x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.

Find the equation of normal to the curve x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.

The equation of normal to the curve x= a cos^(3) theta, y=a sin^(3) theta" at "theta=(pi)/(4) is

Find the slope of the normal to the curve x = a cos^3 theta, y = a sin^3 theta at theta = pi/4

Find the equation of the normal to the curve given by x = cos^3theta , y = sin^3theta at theta=pi/4

Find the equations of tangent to the curve x=1-cos theta,y=theta-sin theta at theta=(pi)/(4)

The equation of normal to the curve x= sin theta and y=cos 2 theta" at "theta =(pi)/(6) is

The equation of the normal to the curve x=a\ cos^3theta,\ \ y=a\ sin^3theta at the point theta=pi//4 is (a) x=0 (b) y=0 (c) x=y (d) x+y=a

Show that the equation of the normal to the curve x=a cos ^(3) theta, y=a sin ^(3) theta at 'theta ' is x cos theta -y sin theta =a cos 2 theta .