[" 116.Let "k" be an integer such that the triangle with "],[" vertices "(k,-3k),(5,k)" and "(-k,2)" has area "],[28" sq.units.Then the orthocentre of this triangle "],[" is at the point "]

Let k be an integer such that the triangle with vertices (k,-3k),(5,k) and (-k,2) has area 28sq. units.Then the orthocentre of this triangle is at the point: :(1,-(3)/(4))(2)(2,(1)/(2))(3)(2,-(1)/(2))(4)(1,(3)/(4))

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1) (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1) (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1) (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

If the area of triangle with vertices (-3,0), (3,0) and (0,k) is 9 sq . units then the value of k is

Area of the triangle with vertices (k,0),(1,1) and (0,3) is 5 sq. units. Find the values of k.

If the area of a triangle with vertices (-3,0),(3,0) and (0,0) is 9 sq. units. Then the value of k will be

If the area of a triangle with vertices (-3,0),(3,0) and (0,0) is 9 sq. units. Then the value of k will be

Find the values of k so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq. units.