log_(4)log_(2)x+log_(2)log_(4)x=2

The value of x :satisfying the equation log_(4)(2log_(2)x)+log_(2)(2log_(4)x)=2 is

The sum of solutions of the equation log_(2)x log_(4)x log_(6)x=log_(2)x*log_(4)x+log_(4)x log_(6)x+log_(6)x*log_(2)x is equal to

Domain of the function f(x)=log_(2)(log_(4)(log_(2)(log_(3)(x^(2)+4x-23))) is

If log_(4)2+log_(4)4+log_(4)x+log_(4)16=6 then x =

solve for x if log_(4)log_(3)log_(2)x=0 and log_(e)log_(5)(sqrt(2x+2)-3)=0

If log_(2)log_(3)log_(4)log_(5)A=x , then the value of A is

log_(2)log_(3)log_(4)(x-1)>0

Find x,log_(2)2+log_(3)2+log_(4)2=log_(x)83

Let log_(2)x+log_(4)y+log_(4)z=2log_(9)x+log_(3)y+log_(9)z=2;log_(16)x+log_(16)y+log_(4)z=2. Find the value of (yz)/(x)

Solve for x,y,zlog_(2)x+log_(4)y+log_(4)z=2log_(3)y+log_(9)z+log_(9)x=2log_(4)z+log_(16)x+log_(16)y=2