The work done in rotating a magnet of pole strength `1 A-m` and length `1 cm` through an angle of `60^(@)` from the magnetic meridian is `(H=30A//m)`

Calculate the work done in rotating a magnet of pole strength [10^(-2)] Ampere-m and magnetic length 10 cm through an angle of 60° from its position along the magnetic, meridian. (B = 200T)

The work done in turning a magnet of magnetic moment M by an angle of 90^(@) from the magnetic meridian is n times the corresponding work done to turn through an angle of 60^(@) . What is the value of n ?

The work done in turning a magnet of magnetic moment M through an angle theta from the meridian is

Calculate the work done in rotating a magnet of magnetic moment 3*0JT^-1 through an angle of 60^@ from its position along a magnetic field of strength 0*34xx10^-4T .

Calculate the work done in rotating a bar magnet of magnetic moment 3 JT^-1 through an angle of 60^@ from its position along a magnetic field of strength 0.34 xx 10^-4T