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" 53."quad (2cos theta-1)(2cos2 theta-1)...

" 53."quad (2cos theta-1)(2cos2 theta-1)(2cos4 theta-1)(2cos8 theta-1)=

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The value (2cos theta-1)(2cos2 theta-1)(2cos4 theta-1)(2cos8 theta-1)=

Prove that: (2cos2 theta+1)/(2cos theta+1)=(2cos theta-1)(2cos2 theta-1)(2cos2^(2)theta-1)...(2cos2^(n-1)theta-1)

Prove that: (2cos2^(n)theta+1)/(2cos theta+1)=(2cos theta-1)(2cos2 theta-1)(2cos2^(2)theta-1)...(2cos2^(n-1)theta-1)

For a positive integer n, let f_(n)(theta)=(2cos theta+1)(2cos theta-1)(2cos2 theta-1)(2cos(2^(2))theta-1)...(2cos(2^(n-1))theta-1) Which one of the following hold(s) good?

If theta=(pi)/(8), then what is value of (2cos theta+1)^(10)(2cos2 theta-1)^(10)(2cos theta-1)^(10)(2cos4 theta-1)^(10)?(i)0(ii)1(iii)2(iv)4

If theta=(pi)/(8) , then what is the value of (2cos theta+1)^(10)(2cos2theta-1)^(10)(2cos theta-1)^(10)(2cos4 theta-1)^(10) ?

Prove that, (2 cos theta - 1)(2 cos 2 theta-1)(2 cos2^(2) theta-1)...(2 cos 2^(n-1) theta-1) = (2 cos 2^(n) theta + 1)/(2 cos theta + 1)

(cos3theta)/(2cos2theta-1)=(1)/(2) if

cos theta cos2 theta cos3 theta=(1)/(4)