`U^(235) + n^(1)rarr` fission product + neutron + 3.2`xx 10^(-11)j`. The energy released , when 1g of `u^(235)` finally undergoes fission , is

""_(92)^(235)U+nto""_(92)^(235)Uto fission product + Neutron 3.20xx10^(-11)J . The energy released when 1 g of ""_(92)^(235)U undergoes fission is

The enegry released per fission of .^(235)u is nearly

How much energy is released when 2 mole of U^(235) is fission :

Calculate the amount of energy released when 1 kg of ""_(92)^(235)"U" undergoes fission reaction.

The ._(92)^(235)U absorbs a slow neutron (thermal neutron) & undergoes a fission represented by (i) The energy release E per fission. (ii) The energy release when 1g of ._(92)^(236)U undergoes complete fission. Given : ._(92)^(235)U = 235.1175 am u (atom), ._(56)^(141)Ba = 140.9577 am u (atom), ._(36)^(92)Kr = 91.9264 am u (atom), ._(0)^(1)n = 1.00898 am u .