A convex refracting surface of radius of curvature `20 cm` separates two media of refractive indices `4//3 and 1.60`. An object is placed in the first medium `(mu = 4//3)` at a distance of `200 cm` from the refracting surface. Calculate the position of image formed.

Options

A. `120 cm`
B. `240 cm`
C. `100 cm`
D. `60 cm`

Answer

B

Explanation

Using, `- (mu_(1))/(mu) + (mu_(2))/(v) = (mu_(2) - mu_(1))/(R)`
Here, `R = 20 cm, mu_(1) = 4/3 . Mu_(2) = 1.60, u = - 200 cm`
`:. - (4//3)/(-200) + (1.60)/(v) = (1.60 - (4//3))/(20) rArr v = 240 m`