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An object is placed at a distance of 1.5...

An object is placed at a distance of `1.5 m` from a screen and a convex lens is interposed between them. The magnification produced is `4`. What is the focal length of the lens ?

A

`1m`

B

`0.5 m`

C

`0.24 m`

D

`2 m`

Text Solution

Verified by Experts

The correct Answer is:
C

Here, `m = (v)/(u) = - 4` or ` u = (-v)/(4)`
Also, `|u| + |v| = 1.5`
`v/4 + 5 = 1.5` or `v = 1.2 m` and `u = (-1.2)/(4) = -0.3 m`
`:. f = (uv)/(u- v) = (-0.3 xx 1.2)/(-0.3 xx 1.2) = 0.24 m`
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