A train weighing `1000` quintals is running on a level road with a unifrom speed of `72km//h` If the frictional resistance amounts to 50g wt. per quintal find power in watt, take `g = 9.8ms^(2)`.

A train weghing 1000 quintals is running on a level road ith a uniform speed of 72 km//h .If teh frictional resistance amounts to 50 g wt.per quintal,find power in watt,take g= 9.8 m s^-2 .

A train weighing 100 metric ton is running on a level track with a uniform speed of 72km h^(-1) . If the frictional resistance amounts to 0.5kg per metric ton, find the power of the engine

A train of weight 10^(7)N is running on a travel track with uniform speed of 36 km h^(-1) . The frictional force is 0.5 kg f per quintal. If g = 10 ms^(-2) , power of engine is

A train of weight 10^(7)N is running on a travel track with uniform speed of 36 km h^(-1) . The frictional force is 0.5 kg f per quintal. If g = 10 ms^(-2) , power of engine is

A railway engine weighing 40 metric ton is travelling along a level track at a speed of 54 km H^(-1) What additional power is required to maintain the same speed up an incline of 1 in 49 Take g = 9.8 m//s^(2) and m u = 0.1 .

Calculate the power of an engine , which can just pull a train of mass 5000 quintals up an incline of 1 in 50 at the rate of 54 km//h . The resistance due to friction is 0.8 N //"quintal" . Take g = 9.8 m//s^(2) .

A truck of amss 10 ton is movng up an incline of 1 in 50 with a uniform velocity of 72 km/h. If the resistance opposing the motion of the truck due to friction is 5 kg per ton, the power of the engine is (g=10m//s^(2))