The normal to the curve `2x^2+y^2=12` at the point `(2,2)` cuts the curve again at (A) `(-(22)/9,-2/9)` (B) `((22)/9,2/9)` (C) `(-2,-2)` (D) none of these

Find the slope of normal to the curve 3x^(2) - y^(2) =8 at the point (2,2)

The slope of the tangent line to the curve x+y=xy at the point (2,2) is

Find the equation of the normal to the curve x^2-4y^2=9 at (5,-2)

The equation of the normal to the curve y= e^(-2|x|) at the point where the curve cuts the line x=-(1)/(2), is

Find the equation of the normal to the curve y(x^2+4)=16 at (2,2)

The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is

The co-ordinates of the points on the curve y=x^(2)+3x+4 at which the tangent passes through the origin are (A) (-2,14) (B) (2,14) (C) (2,-2) (D) (-2,2)

The point on the circle (x-3)^2 + (y-4)^2 = 4 which is at least distance from the circle x^2 + y^2 = 1 is : (A) (3/5, 4/5) (B) (9/5, 12/5) (C) (9, 12) (D) none of these

If the normal at theta on (x^(2))/(a^(2))+(y^(2))/(b^(2))=1,(a>b) intersects the curve again at phi then