At what point of curve y=2/3x^3+1/2x^2, ...

At what point of curve `y=2/3x^3+1/2x^2,` the tangent makes equal angle with the axis? `(1/5,5/(24))a n d(-1,-1/6)` `(1/2,4/9)a n d(-1,0)` `(1/3,1/7)a n d(-3,1/2)` `(1/3,4/(47))a n d(-1,-1/3)`

Similar Questions

Explore conceptually related problems

The point on the curve y^2=x where tangent makes 45o angle with x-axis is (1//2,\ 1//4) (b) (1//4,\ 1//2) (c) (4,\ 2) (d) (1,\ 1)

The angle between tangents to the curves y=x^(2) and x^(2)=y^(2) at (1,1) is (A) cos^(-1)(4/5) (B) sin^(-1)(3/5) (C) tan^(-1)(3/4) (D) tan^(-1)(1/3)

The largest number in the sequence 1, 2^(1/2), 3^(1/3), 4^(1/4),..., n^(1/n) is a. 2^(1/2) b. 3^(1/3) c. 5^(1/5) d. 6^(1/6)

Show that the following points are coplanar: (0,\ 4,\ 3),\ (-1,\ -5,\ -3),\ (-2,\ -2,\ 1)a n d\ (1,\ 1,\ -1)dot

Find the angle between the following pairs of line: (x-5)/1=(2y+6)/(-2)=(z-3)/1a n d(x-2)/3=(y+1)/4=(z-6)/5

The angle between the lines (x-1)/1=(y-1)/1=(z-1)/2a n d(x-1)/(-sqrt(3)-1)=(y-1)/(sqrt(3)-1)=(z-1)/4 is cos^(-1)(1/(65)) b. pi/6 c. pi/3 d. pi/4

Find the angle between the following pairs of line: (x-1)/2=(y-2)/3=(z-3)/(-3)a n d(x+3)/(-1)=(y-5)/8=(z-1)/4

Show that the lines (x-1)/3=(y+1)/2=(z-1)/5a n d(x+2)/4=(y-1)/3=(z+1)/(-2) do not intersect.

A point equidistant from the line 4x+3y+2=0,\ 5x-12 y+26=0\ a n d\ 7x+24 y-50=0 is (1,-1) b. (1,1) c. (0,0) d. (0,1)