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The total mechanical energy of an objec...

The total mechanical energy of an object of mass m projected from surface of earth with escape speed is

A

Zero

B

Infinite

C

`-(GMm)/(2R)`

D

`-(GMm)/(3R)`

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The correct Answer is:
To solve the problem of finding the total mechanical energy of an object of mass \( m \) projected from the surface of the Earth with escape speed, we can follow these steps: ### Step 1: Understand Escape Speed The escape speed is the minimum speed required for an object to break free from the gravitational pull of a planet without any additional propulsion. For Earth, the escape speed \( v_e \) is given by the formula: \[ v_e = \sqrt{2gR} \] where \( g \) is the acceleration due to gravity and \( R \) is the radius of the Earth. ### Step 2: Determine Kinetic Energy at Escape Speed When the object is projected with escape speed, its kinetic energy \( KE \) at the surface of the Earth is calculated using the formula: \[ KE = \frac{1}{2}mv_e^2 \] Substituting the expression for escape speed: \[ KE = \frac{1}{2}m(2gR) = mgR \] ### Step 3: Determine Potential Energy at the Surface of the Earth The gravitational potential energy \( PE \) of the object at the surface of the Earth is given by: \[ PE = -\frac{GMm}{R} \] where \( G \) is the universal gravitational constant and \( M \) is the mass of the Earth. ### Step 4: Calculate Total Mechanical Energy The total mechanical energy \( E \) of the object is the sum of its kinetic energy and potential energy: \[ E = KE + PE \] Substituting the expressions for \( KE \) and \( PE \): \[ E = mgR - \frac{GMm}{R} \] ### Step 5: Simplify the Expression Using the relation \( g = \frac{GM}{R^2} \), we can express \( mgR \) as: \[ mgR = m \left( \frac{GM}{R^2} \right) R = \frac{GMm}{R} \] Thus, we can rewrite the total mechanical energy: \[ E = \frac{GMm}{R} - \frac{GMm}{R} = 0 \] ### Conclusion The total mechanical energy of an object of mass \( m \) projected from the surface of the Earth with escape speed is: \[ \boxed{0} \]
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