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If acceleration due to gravity at dis...

If acceleration due to gravity at distance d ` [ < R ] ` from the centre of earth is `beta ` , then its value at distance d above the surface of earth will be [ where R is radius of earth ]

A

`(betaR^(2))/((R+d)^(3))`

B

`(betaR)/(2d)`

C

`(betad)/((R+d)^(3))`

D

`(betaR^(3))/(d(R+d)^(2))`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the acceleration due to gravity at a distance \(d\) above the surface of the Earth, given that the acceleration due to gravity at a distance \(d\) from the center of the Earth is \(\beta\). ### Step 1: Understand the relationship between gravity inside and outside the Earth The acceleration due to gravity at a distance \(d\) from the center of the Earth, where \(d < R\) (the radius of the Earth), is given by: \[ g' = g \left( \frac{d}{R} \right) \] where \(g\) is the acceleration due to gravity at the surface of the Earth. ### Step 2: Relate \(\beta\) to \(g\) From the above equation, we know: \[ \beta = g \left( \frac{d}{R} \right) \] From this, we can express \(g\) in terms of \(\beta\): \[ g = \frac{\beta R}{d} \] ### Step 3: Find the distance above the surface of the Earth The distance above the surface of the Earth when we are at a distance \(d\) from the center of the Earth is given by: \[ h = d - R \] Thus, the distance above the surface of the Earth is \(h\). ### Step 4: Calculate the acceleration due to gravity at height \(h\) The acceleration due to gravity at a height \(h\) above the Earth's surface is given by: \[ g_h = \frac{g}{\left(1 + \frac{h}{R}\right)^2} \] Substituting \(h = d - R\) into the equation: \[ g_h = \frac{g}{\left(1 + \frac{d - R}{R}\right)^2} = \frac{g}{\left(\frac{d}{R}\right)^2} \] ### Step 5: Substitute \(g\) in terms of \(\beta\) Now substituting \(g = \frac{\beta R}{d}\): \[ g_h = \frac{\frac{\beta R}{d}}{\left(\frac{d}{R}\right)^2} = \frac{\beta R}{d} \cdot \frac{R^2}{d^2} = \frac{\beta R^2}{d^3} \] ### Final Result Thus, the acceleration due to gravity at a distance \(d\) above the surface of the Earth is: \[ g_h = \frac{\beta R^2}{d^3} \]
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