Home
Class 12
PHYSICS
A raindrop of radius 0.2 mm falls throug...

A raindrop of radius 0.2 mm falls through air: If the viscosity of air is 18 `xx 10^(-6)` Pl, find the viscous drag acting on the drop when its speed is 1 m `s^(-1)`.

Text Solution

Verified by Experts

Radius of raindrop,-a- = 0.2 mm
= `0.2 xx 10^(-3)` m
Air viscosity `eta = 18 xx 10^(-6)` PI
Speed of fall of raindrop, v = 1 m `s^(-1)`
From Stokes. law
Viscous force F = `6 pi eta a v`
`6pi xx 18 xx 10^(-6) xx0.2xx10^(-3)xx1`
`67.8xx10^(-9)`N
Promotional Banner

Similar Questions

Explore conceptually related problems

A rain drop of radius 0.3 mm has a terminal velocity in air 1m/s. the viscosity of air is 18xx10^(-5) poise. The viscous force on it is-

A raindrop of radius 0.3 mm has a terminal velocity in air 1ms^(-1) . The viscosity of air is 18xx10^(-3) poise. The viscous force on it is

A rain drop of radius 0.3 mm falls through air with a terminal velocity of 1 m/s. The viscosity of air is 18 xx 10^(-6) N-s //m^(2) . Find the viscous force on the rain drop.

A rain drop of radius 0.3 mm has a terminal velocity in "air" = 1 "m/s" . The viscosity of air is 8 xx 10^(–5) poise. The viscous force on it is

A rain drop of radius 0.3 mm falls through air with a terminal viscosity of 1 m s^(-1) . The viscosity of air is 18 xx 10^(-5) poise. The viscous force on the rain drop is

A rain drop of radius 0.5 mm has a terminal velocity in air 2 m/s. If the coefficient of viscosity of air is 1.8xx10^(-4) poise, the viscous drag on the rain drop will be

A rain drop of radius 0.5 mm has a terminal velocity in air 2 ms^(-1) . The viscosity of air is 18 xx 10^(-5)" dyne "cm^(-2)s . Find the viscous force on the rain drop.

A rain drop of radius 0.4 mm falls through air with a terminal velocity of 50 cm s^(-1) . The viscosity of air is 0.019 Pa-s . Find the viscous force on the rain drop.

A drop of water of radius 0.0015 mm is falling in air. If the coefficient of viscosity of air is 1.8 xx 10^(-3)kg//m^(3) , what will be the terminal velocity of the drop? Density of water = 1.0 xx 10^(3) kg//m^(2) and g = 9.8 N//kg . Density of air can be neglected.

A drop of water of radius 0.0015 mm is falling in air .If the cofficient of viscosity of air is 2.0 xx 10^(-5) kg m^(-1)s^(-1) ,the terminal velocity of the drop will be (The density of water = 10^(3) kg m^(-3) and g = 10 m s^(-2) )