Home
Class 12
PHYSICS
The surface tension of a soap solution i...

The surface tension of a soap solution is `30 xx 10^(-3) N m^(-1)`. How much work is done to increase the radius of a soap bubble from 1.5 cm to 3 cm?

Text Solution

Verified by Experts

Hence Surface tension , S = `30xx10^(-3) Nm^(-1)`
Initial radius = 1.5 cm = `1.5xx10^(-2)`cm
Final radius = 3 cm = `3xx10^(-2)`m
Work done = S `xx` Change in surface area
`Sxx2xx4pi(r_(2)^(2) - r_(1)^(2))`
`30xx10^(-3)xx2xxxxpi(9-2.25) xx10^(-4)`
`5.091xx10^(-4)J`
Promotional Banner

Similar Questions

Explore conceptually related problems

The surface tension of a soap solution is 30 xx 10^(-3) N m^(-1) . How much work is done to increase the radius of a soap bubble from 2 cm to 3 cm?

The work done in increasing the radius of a soap bubble from R to 3 R is

The surface tension of a soap solution is 0.03 Nm^(-1). How much work is done to produce a soap bubble of radius 0.05 m

The surface tension of a soap solution is 0.05 Nm^(-1) How much work is done to produce a soap bubble of radius 0.03 m?

The surface tension of soap solution is 0.030 N/m . What is the energy needed to increase the radius of a soap bubble from 4 cm to 6 cm ?

Calculate the surface tension of a liquid if 5 xx 10^(-3)Nm^(-1) of work is done to increase the surface area of a liquid film from 4 cm xx 3" cm to 8 cm "xx "5 cm."

The surface tension of soap solution is 10 xx 10^(-2) n/m . The amount of work done in blowing a soap bubble of radius 2 cm is

Surface tension of soap solution is 2 xx 10^(-2) N//m . The work done in producing a soap bubble of radius 2 cm is

The surface tension of a soap solution is 2xx10^(-2) N//m . To blow a bubble of radius 1cm, the work done is