If pressure at the half depth of a lake is equal to `3/4` times the pressure at its bottom, then find the depth of the lake. [Take g = 10 m/`s^(2)`]

If pressure at half the depth of a lake is equal to 2//3 pressure at the bottom of the lake then what is the depth of the lake ?

If the pressure at half of the lake is equal to 1/3 pressure at the bottom of the lake, what is the depth of the take? ("assume" g=10m//s^(2), atm=1xx10^(5) and rho=10^(3)kgm^(-3))

If the pressure at half the depth of a tank is equal to 2/3 the pressure at the bottom of the tank, then the height of the water column in the tank is ("Atmospheric pressure "=10^5N//m^2 )

The base of a ractangular vessel is 10 cm xx 15 cm . It is taken at a depth of 4 m into the water. What is the pressure and thrust on the base of the vessel? Take g = 10ms^(-2) . Density of water = 10^(3) kg m^(-3) .

When air bubble comes from bottom to the top of a lake its radius becomes n times. If temprerature remains constant through out the lake the depth of the lake will be.

As an air bubble rises from the bottom of a lake to the surface, its volume is doubled. Find the depth of the lake. Take atmospheric pressure = 76 cm of Hg.

Calculate the depth of a well if the pressure at its bottom is 15 times that at a depth of 3 metres. Atmospheric pressure is 10 m column of water.

A diver in water at a depth of 10 m is under _______ the atmospheric pressure.

The pressure at the bottom of a lake due to water is 4.9xx 10^(6)N//m^(2) . What is the depth of the lake?