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A pendulum clock consists of na iron rod...

A pendulum clock consists of na iron rod connected toa small, heavy bob. If it is desisgned to keep correct time at `20^(@) C`, how fast or slow will it go in 24 hours at `40^@ C?` Coefficient o f linear expansion of iron `= 1.2 xx 10^(-5 @) C^(-1)`.

Text Solution

Verified by Experts

`T=2pisqrt(l/g)`
`implies(DeltaT)/(T)=(1)/(2).(Deltal)/(l).proptheta=(1)/(2)xx(1.2xx10^(-5))xx(20)`
`1.2xx10^(-4)`
Time period increse
Clock goes slow
Hence the time lost 24 hour =`24 hour xx(DeltaT)/(T)`
`(24xx3600)xx1.2xx10^(-4)`
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