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Consider two rods of same length and dif...

Consider two rods of same length and different specific heats (`S_1` and `S_2`), conductivities `K_1` and `K_2` and area of cross section (`A_1` and `A_2`) and both having temperature `T_1` and `T_2` at their ends. If the rate of heat loss due to conduction is equal then

A

`K_(1)A_(1)=K_(2)A_(2)`

B

`(K_(1)A_(1))/(S_(1))=(K_(2)A_(2))/(S_(2))`

C

`K_(2)A_(1)=K_(1)A_(2)`

D

`(K_(2)A_(1))/(S_(2))=(K_(1)A_(2))/(S_(1))`

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