A 2.5 kg collar is attached to a spring of spring constant `250 Nm^(-1)` . It slides without friction over a horizontal surface . It is displaced from its equilibrium position by 20 cm and releasd. Calculate the period of osciallation and the maximum speed.

Explanation

The period of oscillation , `T= 2pi sqrt((m)/(k)) =2pi sqrt(( 2.5 )/( 250))= ( 2 xx 3.14 )/( 0.63) s`
Maximum speed `= V_(m) = A omega = 0.2 sqrt( (k)/(m)) = 0.2 xx sqrt((250 )/( 2.5)) = 0.2 xx 10 = 2 ms^(-1)`