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For examples , find the potential energy of the block at 0.05 m from the mean position

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To find the potential energy of the block at a distance of 0.05 m from the mean position, we can follow these steps: ### Step 1: Understand the System We have a mass attached to a spring with spring constant \( k \). The mean position is the equilibrium position where the spring force balances the weight of the mass. ### Step 2: Identify the Displacement The displacement from the mean position is given as \( x = 0.05 \, \text{m} \). ...
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A block whose mass is 1 kg is fastened to a spring. The spring has a spring constant of 100N/m. the block is pulled to a distance x=10 cm from its equilibrium position at x=0 on a frictionless surface from rest at t=0. the kinetic energy and potential energy of the block when it is 5 cm away from the mean position is

Example based on potential energy

Examples on potential & potential energy

A block whose mass is 2 kg is fastened on a spring whose spring constant is 100 Nm^(-1) . It is pulled to a distance of 0.1 m from over a frictionless surface and is released at t=0. Calculate the kinetic eneryg of the block when it is 0.05 m away from its mean position.

Force acting on a particle is F=-8x in S.H.M. The amplitude of oscillation is 2 (in m) and mass of the particle is 0.5 kg. The total mechanical energy of the particle is 20 J. Find the potential energy of the particle in mean position (in J).

Can the potential energy at some point other than the mean position?

The potential energy of a particle performing S.H.M. at mean position is

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