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A particle is executing a simple harmoni...

A particle is executing a simple harmonic motion. Its maximum acceleration is `alpha` and maximum velocity is `beta`. Then, its time period of vibration will be

A

`(2pi beta)/(alpha)`

B

`(beta^(2))/(alpha^(2))`

C

`(alpha)/(beta)`

D

`(beta^(2))/(alpha)`

Text Solution

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The correct Answer is:
A
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AAKASH INSTITUTE-OSCILLATIONS-Assignment (Section C) (PREVIOUS YEARS QUESTIONS)
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