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A proton and an electron are placed 1.6 ...

A proton and an electron are placed 1.6 cm apart in free speace. Find the magnitude and nature of electrostatic force between them.

Text Solution

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Using Coulomb.s law
`F=(Q_(1)Q_(2))/(4pi epsilon_(0)r^(2))=(9xx10^(9)xx(1.6xx10^(-19))(-1.6xx10^(-19)))/((1.6xx10^(-2))^(2))=-9xx10^(-25)` N
Negative sign indicates that the force is attractive in nature.
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