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A plastic rod of length 2.2m and radius ...

A plastic rod of length 2.2m and radius 3.6 mm carries a negative charge of `3.8xx10^(-7) C` spread uniformly over its surface. What is the electric field near the mid-point of the rod, at a point on its surface?

Text Solution

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Rod is assumed to be of infinite length
So `E=(lambda)/(2pi epsilon_(0)r)=(2lambda)/(4pi epsilon_(0)r)=9xx10^(9)xx(2xx3.8xx10^(-7))/(2.2)xx(2)/(3.6xx10^(-3))=8.6xx10^(5)` N/C
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