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Two identical small bodies each of mass ...

Two identical small bodies each of mass m and charge q are suspended from two strings each of length l from a fixed point. This whole system is taken into an orbiting artificial satellite, then find the tensio in strings

A

`(Kq^(2))/(l^(2))+2" mg"`

B

`(Kq^(2))/(4l^(2))+2" mg"`

C

`(Kq^(2))/(l^(2))`

D

`(Kq^(2))/(4l^(2))`

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Knowledge Check

  • Three identical point charges, each of mass m and charge q, hang from three strings as shown in fig. The value of q in term of m, L, and q is

    A
    `q=sqrt((16//5)pi epsilon_(0)mg L^(2)sin^(2)theta tan theta)`
    B
    `q=sqrt((16//15)pi epsilon_(0)mg L^(2)sin^(2)theta tan theta)`
    C
    `q=sqrt((15//16)pi epsilon_(0)mg L^(2)sin^(2)theta tan theta)`
    D
    none of these

  • Two small balls having equal positive charge Q (coulomb) on each are suspended by two insulated string of equl length L meter, from a hook fixed to a stand. The whole set-up is taken in satellite into space where there is no gravity (state of weightlessness). Then the angle between the string and tension in the string is

    A
    `180^(@),(1)/(4piepsilon_(0)).(Q^(2))/((2L)^(2))`
    B
    `90^(@),(1)/(4piepsilon_(0)).(Q^(2))/(L^(2))`
    C
    `180^(@),(1)/(4piepsilon_(0)).(Q^(2))/(2L^(2))`
    D
    `180^(@),(1)/(4piepsilon_(0)).(QL)/(4L^(2))`

  • Two small balls having equal positive charge Q (coulumb) on each suspended by two insulating strings of equal length L (metre) from a hook fixed to a stand. The whole set-up is taken in a satellite into space where there is no gravity (state of weightlessness). Then tension (newtons) in each string is:

    A
    `(Q^(2))/(4piin_(0)L^(2))`
    B
    `(Q^(2))/(8piin_(0) L^(2))`
    C
    `(Q^(2))/(12 pi in_(0)L^(2))`
    D
    `(Q^(2))/(16 pi in_(0)L^(2))`

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