Home
Class 12
PHYSICS
How many electrons should be removed fro...

How many electrons should be removed from a coin of mass `1.6g`, so that it may float in an electric field of intensity of `10^(9)NC^(-1)` directed upward. (take `g= 10m//s^(2)`)

A

`9.8xx10^(7)`

B

`9.8xx10^(5)`

C

`9.8xx10^(3)`

D

`9.8xx10^(1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

a charged particle of mass 2 mg hang in air in an electric field of strength 4 N/C directed upwards. the charge on the particle would be (g=10m/s^2)

Find the number of electron that should be removed from a coin so that it acquires a charge of 10^(-6) coulomb

A diople consisting of an electron and a proton separated by a distance of 4xx10^(-10) m is situated in an electric field of intensity 3xx10^(5) NC^(-1) at an angle of 30^(@) with the field. Calculate the diople moment and the torque acting on it. Charge e on an electron = 1*6xx10^(-19) C.

A water droplet of radius 1 micron in Milikan oil drop appartus in first held stationary under the influence of an electric field of intensity 5.1xx10^(4) NC^(-1) . How many excess electrons does it carry ? Take e = 1.6xx10^(-19) C, g = 9.8 ms^(-2) and density of water of = 10^(3) kg m^(-3) .

4xx10^(10) electrons are removed from a neutral metal sphere of diameter 20 cm placed in air. The magnitude of the electric field (in NC^(-1) ) at a distance of 20 cm from its centre is

An electron entering field normally with a velocity 4 xx 10^7 ms^(-1) travels a distance of 0.10 m in an electric field of intensity 3200 Vm^(-1) . What is the deviation from its path?

A charged particle of mass 0.003 g is held stationary in space by placing it in a downward direction of electric field of 6xx10^(4)NC^(-1) . Then, the magnitude of charge is

In Millikan's oil drop experiment, an oil drop mass 60 xx 10^(-6) kg is balanced by an electric field of 10^(6) V//m . The charge in coulomb on the drop, assuming g = 10 m//s^(2) is

How much energy will be needed for a body of mass 100kg to escape from the earth- (G = 10M//S^(2) and radius of earth = 6.4 xx 10^(6) m)