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If the number of electric lines of force...

If the number of electric lines of force emerging out of a closed surfsace is 1000, then the charge enclosed by the surface is

A

`8.854xx10^(-9)` C

B

`8.854xx10^(-4)` C

C

`8.854xx10^(-1)` C

D

8.854 C

Text Solution

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The correct Answer is:
To find the charge enclosed by a closed surface when the number of electric lines of force emerging from it is given, we can use Gauss's law. Here's a step-by-step solution: ### Step 1: Understand the relationship between electric lines of force and electric flux The number of electric lines of force emerging from a closed surface is equal to the electric flux (\( \Phi_E \)) through that surface. Therefore, if there are 1000 electric lines of force, we can say: \[ \Phi_E = 1000 \] ### Step 2: Apply Gauss's Law According to Gauss's law, the electric flux through a closed surface is related to the charge (\( q \)) enclosed by that surface: \[ \Phi_E = \frac{q}{\epsilon_0} \] where \( \epsilon_0 \) is the permittivity of free space, approximately equal to \( 8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2 \). ### Step 3: Rearrange the equation to find the enclosed charge From the equation above, we can rearrange it to solve for the charge \( q \): \[ q = \Phi_E \cdot \epsilon_0 \] ### Step 4: Substitute the known values Now substitute the values we have: \[ q = 1000 \cdot (8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2) \] ### Step 5: Calculate the charge Now, perform the multiplication: \[ q = 1000 \cdot 8.85 \times 10^{-12} = 8.85 \times 10^{-9} \, \text{C} \] ### Final Answer Thus, the charge enclosed by the surface is: \[ \boxed{8.85 \times 10^{-9} \, \text{C}} \]
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