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A charged cloud system produces an elect...

A charged cloud system produces an electric field in the air near the earth's surface. A particle of charge `-2xx10^(-9)` C is acted on by a downward electrostatic force of `3xx10^(-6)` N when placed in this field. The gravitational and electrostatic force, respectively, exerted on a proton placed in this field are

A

`1.64xx10^(-26)N, 2.4xx10^(-16)` N

B

`1.64xx10^(-26)N, 1.5xx10^(3)` N

C

`1.56xx10^(-18)N, 2.4xx10^(-16)` N

D

`1.5xx10^(3)N, 2.4xx10^(-16)` N

Text Solution

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The correct Answer is:
To solve the problem, we need to find the gravitational and electrostatic forces acting on a proton placed in the electric field produced by a charged cloud system. Let's break down the solution step by step. ### Step 1: Determine the Electric Field (E) We know that the electrostatic force (F) acting on a charge (Q) in an electric field (E) is given by the equation: \[ F = Q \cdot E \] From the problem, we have: - The charge of the particle \( Q = -2 \times 10^{-9} \, \text{C} \) - The electrostatic force \( F = 3 \times 10^{-6} \, \text{N} \) (acting downward) Using the above equation, we can rearrange it to find the electric field (E): \[ E = \frac{F}{Q} \] Substituting the values: \[ E = \frac{3 \times 10^{-6} \, \text{N}}{-2 \times 10^{-9} \, \text{C}} \] Calculating this gives: \[ E = -1.5 \times 10^{3} \, \text{N/C} \] ### Step 2: Calculate the Electrostatic Force on the Proton The charge of a proton \( Q_p \) is: \[ Q_p = 1.6 \times 10^{-19} \, \text{C} \] The electrostatic force \( F_{e} \) on the proton in the electric field is given by: \[ F_{e} = Q_p \cdot E \] Substituting the values: \[ F_{e} = 1.6 \times 10^{-19} \, \text{C} \cdot (-1.5 \times 10^{3} \, \text{N/C}) \] Calculating this gives: \[ F_{e} = -2.4 \times 10^{-16} \, \text{N} \] ### Step 3: Calculate the Gravitational Force on the Proton The gravitational force \( F_{g} \) acting on the proton can be calculated using: \[ F_{g} = m_p \cdot g \] Where: - The mass of the proton \( m_p = 1.67 \times 10^{-27} \, \text{kg} \) - The acceleration due to gravity \( g = 9.8 \, \text{m/s}^2 \) Substituting the values: \[ F_{g} = 1.67 \times 10^{-27} \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \] Calculating this gives: \[ F_{g} = 1.64 \times 10^{-26} \, \text{N} \] ### Final Answers - The electrostatic force on the proton is \( F_{e} = -2.4 \times 10^{-16} \, \text{N} \) (upward). - The gravitational force on the proton is \( F_{g} = 1.64 \times 10^{-26} \, \text{N} \) (downward).
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