A slep-up transformer operates on 220 V line and supplies 2.2 A. The ratio of primary and secondary winding is 11 : 50, The output voltage in the secondary is

Options

A. 220 V
B. 100 V
C. 1000 V
D. 0 V

Answer

To find the output voltage in the secondary coil of a step-up transformer, we can use the relationship between the primary and secondary voltages and the number of turns in the coils. Here’s a step-by-step solution:

### Step 1: Understand the given information
- The primary voltage \( E_P = 220 \, V \)
- The current in the primary \( I_P = 2.2 \, A \)
- The turns ratio \( \frac{N_P}{N_S} = \frac{11}{50} \)

### Step 2: Determine the turns ratio
From the given turns ratio \( \frac{N_P}{N_S} = \frac{11}{50} \), we can find the ratio of the secondary to primary turns:
\[ \frac{N_S}{N_P} = \frac{50}{11} \]

### Step 3: Use the transformer voltage relationship
The relationship between the primary and secondary voltages in a transformer is given by:
\[ \frac{E_S}{E_P} = \frac{N_S}{N_P} \]
Substituting the known values:
\[ \frac{E_S}{220} = \frac{50}{11} \]

### Step 4: Solve for the secondary voltage \( E_S \)
Now, we can rearrange the equation to solve for \( E_S \):
\[ E_S = E_P \times \frac{N_S}{N_P} \]
Substituting the values:
\[ E_S = 220 \times \frac{50}{11} \]

### Step 5: Calculate \( E_S \)
Calculating the right-hand side:
\[ E_S = 220 \times \frac{50}{11} = 220 \times 4.5454 \approx 1000 \, V \]

### Conclusion
The output voltage in the secondary coil is:
\[ E_S \approx 1000 \, V \]